7^3x+5=(1/7)^x-1

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Solution for 7^3x+5=(1/7)^x-1 equation: 



7^3x+5=(1/7)^x-1

We move all terms to the left:

7^3x+5-((1/7)^x-1)=0



Domain of the equation: 7)^x-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

7^3x-((+1/7)^x-1)+5=0

We multiply all the terms by the denominator


7^3x*7)^x-1)-((+5*7)^x-1)+1=0

We add all the numbers together, and all the variables

7^3x*7)^x-1)-(35^x-1)+1=0

Wy multiply elements

49x^4=0

We do not support expression: x^4

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